[Dwarf-Discuss] arm literal pool
Metzger, Markus T
markus.t.metzger at intel.com
Tue Sep 15 23:52:25 PDT 2009
>From: dwarf-discuss-bounces at lists.dwarfstd.org [mailto:dwarf-discuss-bounces at lists.dwarfstd.org] On
>Behalf Of ranjith kumar
>1) Given an ARM executable, how to know weather a given address
>contains an 'arm instruction' or 'literal pool' ??
Afaik, ARM uses mapping symbols. $a would start an ARM code region, $t a Thumb code region, $d a data region. The region lasts until the next mapping symbol.
You should find this information in the ARM EABI - it's (or had been) available from their web-site.
>2) What happens when we strip that binary? Can we still determine
>whether given address contains an 'arm instruction' or 'literal
The mapping symbols are part of the symbol table and should not be stripped. I guess you could ask your linker to remove them, though.
>3)Can libelf/libdwarf libraries determine whether given address
>contains an 'arm instruction' or 'literal pool' even after that
>library has been stripped? Where can I find sample programs which uses
>libelf/libdwarf libraries and will tell whether given address
>contains an 'arm instruction' or 'literal pool' ?
Give it a try.
>4) How debuggers build control flow graph from an executable, when
>'literal pool' appears in between 'instructions'?
Control should always flow around literal pools. I don't think you even need to be aware of literal pools to construct a control flow graph. As long as you don't mix modes, I guess you may even ignore mapping symbols completely.
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